195w-10w^2=0

Solution for 195w-10w^2=0 equation:

195w-10w^2=0

a = -10; b = 195; c = 0;
Δ = b2-4ac
Δ = 1952-4·(-10)·0
Δ = 38025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{38025}=195$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(195)-195}{2*-10}=\frac{-390}{-20}
=19+1/2
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(195)+195}{2*-10}=\frac{0}{-20}
=0
$